Back to Grade 8
Solve systems by elimination
Questions at easy, medium and hard levels. Pick a level and get a fresh set every time, with instant feedback.
Learn it Multiply one or both equations so a variable has opposite coefficients, then add to eliminate it. If the variables cancel and you get $0 = 5$, there is no solution; if you get $0 = 0$, there are infinitely many.
Example: $3x + 2y = 16$ and $5x - 4y = -10$
- Multiply the first by 2: $6x + 4y = 32$.
- Add to the second: $11x = 22$, $x = 2$.
- $3(2) + 2y = 16$, $y = 5$. Solution: $(2, 5)$.
Loading questions…